{"id":8520,"date":"2025-01-03T17:15:11","date_gmt":"2025-01-03T14:15:11","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/"},"modified":"2025-01-03T17:15:11","modified_gmt":"2025-01-03T14:15:11","slug":"dizinin-bolunme-yollarinin-sayisi-leetcode-2270","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/","title":{"rendered":"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)"},"content":{"rendered":"<p>Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)<\/p>\n<p>LeetCode&#8217;daki 2270 numaral\u0131 problem olan &#8220;Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131&#8221;, ilgin\u00e7 bir dinamik programlama problemidir.  Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor.  Bu yaz\u0131da, problemi ad\u0131m ad\u0131m inceleyecek, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve farkl\u0131 yakla\u015f\u0131mlar\u0131 kar\u015f\u0131la\u015ft\u0131raca\u011f\u0131z.<\/p>\n<h2>Problemin Tan\u0131m\u0131<\/h2>\n<p>Sorun, bir tam say\u0131lar dizisi nums al\u0131yor.  Hedefimiz, bu diziyi iki alt diziye b\u00f6lmek ve bu iki alt dizinin toplamlar\u0131n\u0131n fark\u0131n\u0131n mutlak de\u011ferinin, verilen bir k de\u011ferinden k\u00fc\u00e7\u00fck veya ona e\u015fit olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmakt\u0131r.  \u00d6rne\u011fin, nums = [1,2,3,4,5] ve k = 3 ise,  toplamlar\u0131n\u0131n fark\u0131 3&#8217;ten k\u00fc\u00e7\u00fck veya e\u015fit olan b\u00f6l\u00fcnme say\u0131s\u0131n\u0131 bulmal\u0131y\u0131z.<\/p>\n<h2>\u00c7\u00f6z\u00fcm Y\u00f6ntemleri<\/h2>\n<p>Bu problemi \u00e7\u00f6zmek i\u00e7in birka\u00e7 farkl\u0131 yol izlenebilir.  En yayg\u0131n y\u00f6ntemlerden biri, dinamik programlama yakla\u015f\u0131m\u0131d\u0131r.  Dinamik programlama ile, daha \u00f6nce hesaplad\u0131\u011f\u0131m\u0131z alt problemlerin sonu\u00e7lar\u0131n\u0131 kullanarak, daha b\u00fcy\u00fck problemleri daha verimli bir \u015fekilde \u00e7\u00f6zebiliriz.  Bu y\u00f6ntemde, \u00f6ncelikle dizinin toplam\u0131n\u0131 hesaplar\u0131z. Ard\u0131ndan, dizinin yar\u0131s\u0131na kadar olan toplamlar\u0131 i\u00e7eren bir DP tablosu olu\u015ftururuz.  Bu tablonun her bir h\u00fccresi, o toplama ula\u015fmak i\u00e7in ka\u00e7 farkl\u0131 yol oldu\u011funu temsil eder.  Son olarak, bu tablodan, toplamlar\u0131n fark\u0131n\u0131n k&#8217;dan k\u00fc\u00e7\u00fck veya e\u015fit oldu\u011fu b\u00f6l\u00fcnme say\u0131s\u0131n\u0131 hesaplayabiliriz.<\/p>\n<h3>Dinamik Programlama Uygulamas\u0131 (Python)<\/h3>\n<pre><code>\ndef waysToSplitArray(nums, k):\n    n = len(nums)\n    total_sum = sum(nums)\n    dp = [0] * (total_sum \/\/ 2 + 1)\n    dp[0] = 1\n\n    for num in nums:\n        for i in range(total_sum \/\/ 2, num - 1, -1):\n            dp[i] += dp[i - num]\n\n    count = 0\n    for i in range(total_sum \/\/ 2 + 1):\n        if abs(total_sum - 2 * i) <= k:\n            count += dp[i]\n    return count\n\n<\/code><\/pre>\n<p>Bu kod, dinamik programlama yakla\u015f\u0131m\u0131n\u0131 kullanarak problemi \u00e7\u00f6zmektedir.  \u00d6ncelikle dizinin toplam\u0131n\u0131 hesaplar, daha sonra DP tablosunu olu\u015fturur ve doldurur. Son olarak,  kriteri sa\u011flayan b\u00f6l\u00fcnme say\u0131s\u0131n\u0131 sayar ve sonucu d\u00f6nd\u00fcr\u00fcr.  Ancak, bu yakla\u015f\u0131m\u0131n zaman karma\u015f\u0131kl\u0131\u011f\u0131 O(n*sum) \u015feklindedir. Bu nedenle, \u00e7ok b\u00fcy\u00fck diziler i\u00e7in performans sorunlar\u0131 ya\u015fanabilir.  Daha verimli algoritmalar ara\u015ft\u0131r\u0131labilir.  <\/p>\n<p>Ayr\u0131ca, problemin \u00e7\u00f6z\u00fcm\u00fcnde,  geriye do\u011fru arama (backtracking) veya b\u00f6l ve y\u00f6net gibi farkl\u0131 yakla\u015f\u0131mlar da kullan\u0131labilir.  Ancak, bu yakla\u015f\u0131mlar\u0131n karma\u015f\u0131kl\u0131\u011f\u0131 ve performans\u0131, dinamik programlamaya g\u00f6re daha az verimli olabilir.<\/p>\n<h2>Optimizasyonlar ve Geli\u015ftirmeler<\/h2>\n<p>Verilen \u00e7\u00f6z\u00fcm, b\u00fcy\u00fck girdiler i\u00e7in zaman karma\u015f\u0131kl\u0131\u011f\u0131ndan dolay\u0131 yava\u015flayabilir.  Daha verimli bir \u00e7\u00f6z\u00fcm i\u00e7in,  alt problemlerin sonu\u00e7lar\u0131n\u0131 \u00f6nbelle\u011fe alma veya daha geli\u015fmi\u015f algoritmalar kullanma gibi optimizasyonlar d\u00fc\u015f\u00fcn\u00fclebilir.  \u00d6rne\u011fin,  daha karma\u015f\u0131k bir DP tablosu yap\u0131s\u0131 veya farkl\u0131 bir veri yap\u0131s\u0131 kullan\u0131m\u0131 performans\u0131 art\u0131rabilir.  Bu konuda daha fazla ara\u015ft\u0131rma yap\u0131labilir. <\/p>\n<p>Bu problemin \u00e7\u00f6z\u00fcm\u00fc, \u00e7e\u015fitli algoritma ve veri yap\u0131lar\u0131 konusundaki bilgilerimizi test etmemizi ve algoritmik d\u00fc\u015f\u00fcnme becerilerimizi geli\u015ftirmemizi sa\u011flar.  Bu t\u00fcr problemler, yaz\u0131l\u0131m geli\u015ftirme alan\u0131nda kar\u015f\u0131la\u015fabilece\u011fimiz karma\u015f\u0131k problemleri \u00e7\u00f6zme becerilerimizi geli\u015ftirmek i\u00e7in idealdir.<\/p>\n<p>Daha fazla algoritma ve veri yap\u0131s\u0131 \u00f6rne\u011fi i\u00e7in <a href=\"https:\/\/fatihsoysal.com\">fatihsoysal.com<\/a> sitesini ziyaret edebilirsiniz.<\/p>\n<p>Ba\u015fka bir faydal\u0131 kaynak olarak LeetCode'un problem sayfas\u0131n\u0131 inceleyebilirsiniz: <a href=\"https:\/\/leetcode.com\/problems\/number-of-ways-to-split-array\/\">LeetCode 2270<\/a><\/p>\n<p>#Etiketler: Dizinin B\u00f6l\u00fcnme Yollar\u0131, LeetCode 2270, Dinamik Programlama, Algoritma, Veri Yap\u0131lar\u0131, Python, Programlama, Kodlama, Yaz\u0131l\u0131m Geli\u015ftirme,  Optimizasyon<\/p>\n","protected":false},"excerpt":{"rendered":"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270) LeetCode&#8217;daki 2270 numaral\u0131 problem olan &#8220;Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131&#8221;, ilgin\u00e7 bir dinamik&hellip;","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"csco_page_header_type":"","csco_page_load_nextpost":"","csco_page_subscribe_form":"","csco_page_contact_form":"","footnotes":""},"categories":[1],"tags":[],"class_list":{"0":"post-8520","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-genel","7":"cs-entry","8":"cs-video-wrap"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v20.5 (Yoast SEO v25.3.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)<\/title>\n<meta name=\"description\" content=\"LeetCode&#039;daki 2270 numaral\u0131 problem olan &quot;Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131&quot;, ilgin\u00e7 bir dinamik programlama problemidir. Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor. Bu yaz\u0131da, problemi ad\u0131m ad\u0131m inceleyecek, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve farkl\u0131 yakla\u015f\u0131mlar\u0131 kar\u015f\u0131la\u015ft\u0131raca\u011f\u0131z.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)\" \/>\n<meta property=\"og:description\" content=\"LeetCode&#039;daki 2270 numaral\u0131 problem olan &quot;Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131&quot;, ilgin\u00e7 bir dinamik programlama problemidir. Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor. Bu yaz\u0131da, problemi ad\u0131m ad\u0131m inceleyecek, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve farkl\u0131 yakla\u015f\u0131mlar\u0131 kar\u015f\u0131la\u015ft\u0131raca\u011f\u0131z.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\" \/>\n<meta property=\"og:site_name\" content=\"Kodlar\u0131n Gizemli D\u00fcnyas\u0131\" \/>\n<meta property=\"article:published_time\" content=\"2025-01-03T14:15:11+00:00\" \/>\n<meta name=\"author\" content=\"Fatih Soysal\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Fatih Soysal\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"2 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\"},\"author\":{\"name\":\"Fatih Soysal\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\"},\"headline\":\"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)\",\"datePublished\":\"2025-01-03T14:15:11+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\"},\"wordCount\":593,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/#respond\"]}],\"copyrightYear\":\"2025\",\"copyrightHolder\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#organization\"}},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\",\"url\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\",\"name\":\"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)\",\"isPartOf\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#website\"},\"datePublished\":\"2025-01-03T14:15:11+00:00\",\"description\":\"LeetCode'daki 2270 numaral\u0131 problem olan \\\"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131\\\", ilgin\u00e7 bir dinamik programlama problemidir. Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor. Bu yaz\u0131da, problemi ad\u0131m ad\u0131m inceleyecek, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve farkl\u0131 yakla\u015f\u0131mlar\u0131 kar\u015f\u0131la\u015ft\u0131raca\u011f\u0131z.\",\"breadcrumb\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Anasayfa\",\"item\":\"https:\/\/fatihsoysal.com\/blog\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#website\",\"url\":\"https:\/\/fatihsoysal.com\/blog\/\",\"name\":\"Fatihsoysal.com\",\"description\":\"Blog - Yaz\u0131l\u0131m D\u00fcnyas\u0131 Tecr\u00fcbelerim\",\"publisher\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/fatihsoysal.com\/blog\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"tr\"},{\"@type\":[\"Person\",\"Organization\"],\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\",\"name\":\"Fatih Soysal\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/image\/\",\"url\":\"https:\/\/fatihsoysal.com\/blog\/wp-content\/uploads\/2024\/04\/cropped-replicate-prediction-3kgg1hgjn5rgp0cf0p5tr0jw7w-1.png\",\"contentUrl\":\"https:\/\/fatihsoysal.com\/blog\/wp-content\/uploads\/2024\/04\/cropped-replicate-prediction-3kgg1hgjn5rgp0cf0p5tr0jw7w-1.png\",\"width\":512,\"height\":512,\"caption\":\"Fatih Soysal\"},\"logo\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/image\/\"},\"description\":\"Kullan\u0131m ve kodlama m\u00fckemmeliyetini odak alan uygulamalar olu\u015fturma deneyimine sahip, profesyonel olarak 15+ y\u0131l \u00fczeri deneyime sahip bir yaz\u0131l\u0131m m\u00fchendisi.\",\"url\":\"https:\/\/fatihsoysal.com\/blog\/author\/fatihsoysal\/\"}]}<\/script>\n<!-- \/ Yoast SEO Premium plugin. -->","yoast_head_json":{"title":"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)","description":"LeetCode'daki 2270 numaral\u0131 problem olan \"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131\", ilgin\u00e7 bir dinamik programlama problemidir. Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor. Bu yaz\u0131da, problemi ad\u0131m ad\u0131m inceleyecek, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve farkl\u0131 yakla\u015f\u0131mlar\u0131 kar\u015f\u0131la\u015ft\u0131raca\u011f\u0131z.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/fatihsoysal.com\/blog\/dizinin-bolunme-yollarinin-sayisi-leetcode-2270\/","og_locale":"tr_TR","og_type":"article","og_title":"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131 (LeetCode 2270)","og_description":"LeetCode'daki 2270 numaral\u0131 problem olan \"Dizinin B\u00f6l\u00fcnme Yollar\u0131n\u0131n Say\u0131s\u0131\", ilgin\u00e7 bir dinamik programlama problemidir. Bu problemde, verilen bir diziyi iki alt diziye b\u00f6lerken, her iki alt dizinin toplamlar\u0131n\u0131n e\u015fit veya belirli bir farktan k\u00fc\u00e7\u00fck olmas\u0131n\u0131 sa\u011flayan yollar\u0131n say\u0131s\u0131n\u0131 bulmam\u0131z gerekiyor. 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