{"id":8273,"date":"2025-01-01T03:45:11","date_gmt":"2025-01-01T00:45:11","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/"},"modified":"2025-01-01T03:45:11","modified_gmt":"2025-01-01T00:45:11","slug":"dairesel-dizideki-bir-sonraki-buyuk-eleman","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/","title":{"rendered":"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman"},"content":{"rendered":"<p><body><\/p>\n<p>Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman<\/p>\n<p>Merhaba! Bu yaz\u0131da, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 nas\u0131l bulaca\u011f\u0131m\u0131z\u0131 detayl\u0131 bir \u015fekilde inceleyece\u011fiz.  Bu problem, algoritma ve veri yap\u0131lar\u0131 konusunda \u00f6nemli bir pratik problemdir ve farkl\u0131 \u00e7\u00f6z\u00fcm yakla\u015f\u0131mlar\u0131 gerektirir.<\/p>\n<p>\u00d6ncelikle, dairesel dizi kavram\u0131n\u0131 a\u00e7\u0131klayal\u0131m. Bir dairesel dizide, dizinin son eleman\u0131ndan sonra tekrar ilk elemana ge\u00e7ilir.  Yani, dizinin sonundaki elemandan sonraki eleman, dizinin ba\u015f\u0131ndaki elemand\u0131r.<\/p>\n<p>\u015eimdi, problemimize daha yak\u0131ndan bakal\u0131m.  Her bir eleman i\u00e7in, kendisinden b\u00fcy\u00fck olan ve kendisinden sonra gelen ilk eleman\u0131 bulmam\u0131z gerekiyor.  Bu eleman, dairesellik nedeniyle dizinin ba\u015f\u0131nda da olabilir.<\/p>\n<h2>\u00c7\u00f6z\u00fcm Y\u00f6ntemleri<\/h2>\n<p>Bu problemi \u00e7\u00f6zmek i\u00e7in birka\u00e7 farkl\u0131 y\u00f6ntem kullanabiliriz.  En yayg\u0131n kullan\u0131lan y\u00f6ntemlerden biri, y\u0131\u011f\u0131n (stack) veri yap\u0131s\u0131n\u0131 kullanmakt\u0131r.  Bu y\u00f6ntemde, her bir eleman\u0131 y\u0131\u011f\u0131na ekler ve y\u0131\u011f\u0131n\u0131n tepesindeki eleman\u0131n kendisinden b\u00fcy\u00fck olup olmad\u0131\u011f\u0131n\u0131 kontrol ederiz.  E\u011fer b\u00fcy\u00fckse, o eleman, \u00f6nceki eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131 olur.  De\u011filse, eleman\u0131 y\u0131\u011f\u0131na eklemeye devam ederiz.  Bu i\u015flem, t\u00fcm dizi elemanlar\u0131 i\u015flenene kadar tekrarlan\u0131r.<\/p>\n<p>A\u015fa\u011f\u0131da, y\u0131\u011f\u0131n kullanarak yaz\u0131lm\u0131\u015f bir JavaScript \u00f6rne\u011fi bulunmaktad\u0131r:<\/p>\n<pre><code class=\"language-javascript\">\nfunction nextGreaterElementCircular(nums) {\n  const n = nums.length;\n  const result = new Array(n).fill(-1); \/\/ Sonu\u00e7 dizisini -1 ile ba\u015flat\u0131yoruz\n  const stack = [];\n\n  for (let i = 0; i < 2 * n; i++) { \/\/ Diziden iki kere ge\u00e7iyoruz (dairesellik i\u00e7in)\n    const num = nums[i % n];\n    while (stack.length > 0 && nums[stack[stack.length - 1]] < num) {\n      result[stack.pop()] = num;\n    }\n    stack.push(i % n);\n  }\n\n  return result;\n}\n\n\/\/ \u00d6rnek kullan\u0131m\nconst nums = [1, 2, 1];\nconst nextGreater = nextGreaterElementCircular(nums);\nconsole.log(nextGreater); \/\/ \u00c7\u0131kt\u0131: [2, -1, 2]\n<\/code><\/pre>\n<p>Bu kodda, \u00f6ncelikle sonu\u00e7 dizisini -1 ile dolduruyoruz.  Daha sonra, diziden iki kere ge\u00e7iyoruz. Bu, daireselli\u011fi sa\u011flamak i\u00e7in gereklidir.  Y\u0131\u011f\u0131n kullanarak, her eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 buluyor ve sonu\u00e7 dizisine yaz\u0131yoruz.<\/p>\n<p>Ba\u015fka bir y\u00f6ntem ise, iki d\u00f6ng\u00fc kullanarak her eleman\u0131 di\u011fer t\u00fcm elemanlarla kar\u015f\u0131la\u015ft\u0131rmakt\u0131r. Ancak, bu y\u00f6ntemin zaman karma\u015f\u0131kl\u0131\u011f\u0131 O(n^2) oldu\u011fundan, b\u00fcy\u00fck diziler i\u00e7in verimsiz olabilir.  Y\u0131\u011f\u0131n tabanl\u0131 y\u00f6ntem ise O(n) zaman karma\u015f\u0131kl\u0131\u011f\u0131na sahiptir. Bu sebeple y\u0131\u011f\u0131n kullan\u0131m\u0131 daha efektiftir.<\/p>\n<h2>Sonu\u00e7<\/h2>\n<p>Bu makalede, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 bulman\u0131n farkl\u0131 yollar\u0131n\u0131 inceledik. Y\u0131\u011f\u0131n kullanarak yaz\u0131lan \u00f6rnek kod, daha verimli bir \u00e7\u00f6z\u00fcm sunmaktad\u0131r.  Umar\u0131m bu yaz\u0131, bu konuda daha fazla bilgi edinmenize yard\u0131mc\u0131 olmu\u015ftur. Daha fazla JavaScript makalesi i\u00e7in <a href=\"https:\/\/fatihsoysal.com\">fatihsoysal.com<\/a> sitesini ziyaret edebilirsiniz.<\/p>\n<p>Faydal\u0131 bulabilece\u011finiz bir di\u011fer kaynak ise <a href=\"https:\/\/dev.to\/dpc\/daily-javascript-challenge-js-61-next-greater-element-in-circular-array-2122\">burada<\/a> bulunmaktad\u0131r.<\/p>\n<p><strong>#Etiketler:<\/strong> JavaScript, Dairesel Dizi, B\u00fcy\u00fck Eleman, Algoritma, Programlama, Kodlama, next greater element, circular array, y\u0131\u011f\u0131n, stack<\/p>\n<p><\/body><br \/>\n<\/html><\/p>\n","protected":false},"excerpt":{"rendered":"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman Merhaba! Bu yaz\u0131da, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir&hellip;","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"csco_page_header_type":"","csco_page_load_nextpost":"","csco_page_subscribe_form":"","csco_page_contact_form":"","footnotes":""},"categories":[1],"tags":[],"class_list":{"0":"post-8273","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-genel","7":"cs-entry","8":"cs-video-wrap"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v20.5 (Yoast SEO v25.3.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman<\/title>\n<meta name=\"description\" content=\"Merhaba! Bu yaz\u0131da, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 nas\u0131l bulaca\u011f\u0131m\u0131z\u0131 detayl\u0131 bir \u015fekilde inceleyece\u011fiz. Bu problem, algoritma ve veri yap\u0131lar\u0131 konusunda \u00f6nemli bir pratik problemdir ve farkl\u0131 \u00e7\u00f6z\u00fcm yakla\u015f\u0131mlar\u0131 gerektirir.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman\" \/>\n<meta property=\"og:description\" content=\"Merhaba! Bu yaz\u0131da, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 nas\u0131l bulaca\u011f\u0131m\u0131z\u0131 detayl\u0131 bir \u015fekilde inceleyece\u011fiz. Bu problem, algoritma ve veri yap\u0131lar\u0131 konusunda \u00f6nemli bir pratik problemdir ve farkl\u0131 \u00e7\u00f6z\u00fcm yakla\u015f\u0131mlar\u0131 gerektirir.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\" \/>\n<meta property=\"og:site_name\" content=\"Kodlar\u0131n Gizemli D\u00fcnyas\u0131\" \/>\n<meta property=\"article:published_time\" content=\"2025-01-01T00:45:11+00:00\" \/>\n<meta name=\"author\" content=\"Fatih Soysal\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Fatih Soysal\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\"},\"author\":{\"name\":\"Fatih Soysal\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\"},\"headline\":\"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman\",\"datePublished\":\"2025-01-01T00:45:11+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\"},\"wordCount\":437,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#\/schema\/person\/002a254750921dcfd568a99e48240dd1\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/#respond\"]}],\"copyrightYear\":\"2025\",\"copyrightHolder\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#organization\"}},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\",\"url\":\"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/\",\"name\":\"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman\",\"isPartOf\":{\"@id\":\"https:\/\/fatihsoysal.com\/blog\/#website\"},\"datePublished\":\"2025-01-01T00:45:11+00:00\",\"description\":\"Merhaba! 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Bu yaz\u0131da, JavaScript kullanarak dairesel bir dizideki her bir eleman\u0131n bir sonraki b\u00fcy\u00fck eleman\u0131n\u0131 nas\u0131l bulaca\u011f\u0131m\u0131z\u0131 detayl\u0131 bir \u015fekilde inceleyece\u011fiz. Bu problem, algoritma ve veri yap\u0131lar\u0131 konusunda \u00f6nemli bir pratik problemdir ve farkl\u0131 \u00e7\u00f6z\u00fcm yakla\u015f\u0131mlar\u0131 gerektirir.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/fatihsoysal.com\/blog\/dairesel-dizideki-bir-sonraki-buyuk-eleman\/","og_locale":"tr_TR","og_type":"article","og_title":"Dairesel Dizideki Bir Sonraki B\u00fcy\u00fck Eleman","og_description":"Merhaba! 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