{"id":39034,"date":"2026-02-13T00:41:24","date_gmt":"2026-02-12T21:41:24","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/?p=39034"},"modified":"2026-02-13T00:41:24","modified_gmt":"2026-02-12T21:41:24","slug":"replace-metodunun-temel-kullanimi","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/replace-metodunun-temel-kullanimi\/","title":{"rendered":"replace() Metodunun Temel Kullan\u0131m\u0131"},"content":{"rendered":"<p><body><\/p>\n<p>Python, metin i\u015fleme konusunda g\u00fc\u00e7l\u00fc ve esnek ara\u00e7lar sunar. Bu ara\u00e7lardan biri de string nesnelerinin ayr\u0131lmaz bir par\u00e7as\u0131 olan <code>replace()<\/code> metodudur. Bu rehberde, Python&#8217;da <code>replace()<\/code> metodunun ne oldu\u011funu, nas\u0131l kullan\u0131ld\u0131\u011f\u0131n\u0131, farkl\u0131 senaryolarda nas\u0131l uygulanabilece\u011fini ve performans ipu\u00e7lar\u0131n\u0131 detayl\u0131 bir \u015fekilde inceleyece\u011fiz.<\/p>\n<p>Metin verileriyle \u00e7al\u0131\u015f\u0131rken belirli bir alt dizgeyi (substring) ba\u015fka bir alt dizgeyle de\u011fi\u015ftirmek s\u0131k\u00e7a kar\u015f\u0131la\u015f\u0131lan bir ihtiya\u00e7t\u0131r. Veri temizleme, metin formatlama veya kullan\u0131c\u0131 giri\u015flerini d\u00fczenleme gibi bir\u00e7ok alanda <code>replace()<\/code> metodu vazge\u00e7ilmez bir yard\u0131mc\u0131d\u0131r.<\/p>\n<h2>replace() Metodunun Temel Kullan\u0131m\u0131<\/h2>\n<p>Python&#8217;da stringler de\u011fi\u015ftirilemez (immutable) veri tipleridir. Bu, bir string olu\u015fturulduktan sonra i\u00e7eri\u011finin do\u011frudan de\u011fi\u015ftirilemeyece\u011fi anlam\u0131na gelir. <code>replace()<\/code> metodu da bu prensibe uygun olarak \u00e7al\u0131\u015f\u0131r; orijinal stringi de\u011fi\u015ftirmez, bunun yerine istenen de\u011fi\u015fiklikleri i\u00e7eren <strong>yeni bir string d\u00f6nd\u00fcr\u00fcr<\/strong>.<\/p>\n<h3>S\u00f6zdizimi (Syntax)<\/h3>\n<pre><code class=\"language-python\">string.replace(old, new, count)\n<\/code><\/pre>\n<h3>Parametreler<\/h3>\n<ul>\n<li><strong><code>old<\/code> (Zorunlu):<\/strong> De\u011fi\u015ftirilmek istenen alt dizge. Bu parametre, string i\u00e7inde aranan ve yerine ba\u015fka bir de\u011fer konulacak olan deseni temsil eder.<\/li>\n<li><strong><code>new<\/code> (Zorunlu):<\/strong> <code>old<\/code> yerine konulacak olan yeni alt dizge.<\/li>\n<li><strong><code>count<\/code> (\u0130ste\u011fe Ba\u011fl\u0131):<\/strong> De\u011fi\u015fiklik say\u0131s\u0131n\u0131 s\u0131n\u0131rlayan bir tam say\u0131d\u0131r. E\u011fer belirtilirse, string i\u00e7inde bulunan ilk <code>count<\/code> adet <code>old<\/code> alt dizgesi <code>new<\/code> ile de\u011fi\u015ftirilir. Belirtilmezse veya <code>-1<\/code> olarak verilirse, <code>old<\/code> alt dizgesinin t\u00fcm ge\u00e7i\u015fleri de\u011fi\u015ftirilir.<\/li>\n<\/ul>\n<h3>D\u00f6n\u00fc\u015f De\u011feri<\/h3>\n<p><code>replace()<\/code> metodu, t\u00fcm de\u011fi\u015fiklikler yap\u0131ld\u0131ktan sonra ortaya \u00e7\u0131kan <strong>yeni stringi<\/strong> d\u00f6nd\u00fcr\u00fcr. E\u011fer <code>old<\/code> alt dizgesi orijinal string i\u00e7inde bulunamazsa, orijinal stringin bir kopyas\u0131 oldu\u011fu gibi d\u00f6nd\u00fcr\u00fcl\u00fcr.<\/p>\n<h3>Temel Kullan\u0131m \u00d6rnekleri<\/h3>\n<p>A\u015fa\u011f\u0131daki \u00f6rnekler, <code>replace()<\/code> metodunun temel kullan\u0131m\u0131n\u0131 g\u00f6stermektedir:<\/p>\n<h4>\u00d6rnek 1: Basit Bir Alt Dizgeyi De\u011fi\u015ftirme<\/h4>\n<p>Bu \u00f6rnekte, bir kelimeyi ba\u015fka bir kelimeyle de\u011fi\u015ftiriyoruz.<\/p>\n<pre><code class=\"language-python\">metin = \"Merhaba D\u00fcnya!\"\nyeni_metin = metin.replace(\"D\u00fcnya\", \"Python\")\nprint(yeni_metin) # \u00c7\u0131kt\u0131: Merhaba Python!\nprint(metin)      # \u00c7\u0131kt\u0131: Merhaba D\u00fcnya! (Orijinal metin de\u011fi\u015fmedi)\n<\/code><\/pre>\n<h4>\u00d6rnek 2: Birden Fazla Ge\u00e7i\u015fi De\u011fi\u015ftirme<\/h4>\n<p><code>count<\/code> parametresi belirtilmedi\u011finde, <code>old<\/code> alt dizgesinin t\u00fcm ge\u00e7i\u015fleri de\u011fi\u015ftirilir.<\/p>\n<pre><code class=\"language-python\">c\u00fcmle = \"elma, armut, elma, muz, elma\"\nyeni_c\u00fcmle = c\u00fcmle.replace(\"elma\", \"\u00e7ilek\")\nprint(yeni_c\u00fcmle) # \u00c7\u0131kt\u0131: \u00e7ilek, armut, \u00e7ilek, muz, \u00e7ilek\n<\/code><\/pre>\n<h4>\u00d6rnek 3: De\u011fi\u015fiklik Say\u0131s\u0131n\u0131 S\u0131n\u0131rlama (count parametresi)<\/h4>\n<p><code>count<\/code> parametresi ile sadece belirli say\u0131da alt dizgenin de\u011fi\u015ftirilmesini sa\u011flayabiliriz.<\/p>\n<pre><code class=\"language-python\">say\u0131lar = \"1 2 3 1 4 1 5 1\"\nilk_iki_de\u011fi\u015fim = say\u0131lar.replace(\"1\", \"X\", 2)\nprint(ilk_iki_de\u011fi\u015fim) # \u00c7\u0131kt\u0131: X 2 3 X 4 1 5 1\n<\/code><\/pre>\n<h2>Geli\u015fmi\u015f Senaryolar ve Pratik \u0130pu\u00e7lar\u0131<\/h2>\n<p><code>replace()<\/code> metodu, basit kullan\u0131mlar\u0131n\u0131n \u00f6tesinde \u00e7e\u015fitli pratik senaryolarda da olduk\u00e7a kullan\u0131\u015fl\u0131d\u0131r.<\/p>\n<h3>B\u00fcy\u00fck\/K\u00fc\u00e7\u00fck Harf Duyarl\u0131l\u0131\u011f\u0131<\/h3>\n<p><code>replace()<\/code> metodu b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyarl\u0131d\u0131r. Yani, &#8220;Python&#8221; ile &#8220;python&#8221; farkl\u0131 kabul edilir.<\/p>\n<h4>\u00d6rnek: B\u00fcy\u00fck\/K\u00fc\u00e7\u00fck Harf Duyarl\u0131l\u0131\u011f\u0131n\u0131 Y\u00f6netme<\/h4>\n<p>E\u011fer b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyarl\u0131 olmayan bir de\u011fi\u015fim yapmak istiyorsan\u0131z, stringi \u00f6nce <code>lower()<\/code> veya <code>upper()<\/code> metotlar\u0131yla tek bir duruma d\u00f6n\u00fc\u015ft\u00fcrebilirsiniz.<\/p>\n<pre><code class=\"language-python\">metin = \"Python programlama dili \u00e7ok g\u00fc\u00e7l\u00fcd\u00fcr. python \u00f6\u011frenmek keyiflidir.\"\n\n<h2>B\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyarl\u0131 de\u011fi\u015fim<\/h2>\nyeni_metin_duyarli = metin.replace(\"python\", \"Java\")\nprint(f\"Duyarl\u0131: {yeni_metin_duyarli}\")\n<h2>\u00c7\u0131kt\u0131: Duyarl\u0131: Python programlama dili \u00e7ok g\u00fc\u00e7l\u00fcd\u00fcr. Java \u00f6\u011frenmek keyiflidir.<\/h2>\n\n<h2>B\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyars\u0131z de\u011fi\u015fim (ge\u00e7ici olarak k\u00fc\u00e7\u00fck harfe \u00e7evirerek)<\/h2>\nyeni_metin_duyarsiz = metin.lower().replace(\"python\", \"Java\")\nprint(f\"Duyars\u0131z: {yeni_metin_duyarsiz}\")\n<h2>\u00c7\u0131kt\u0131: Duyars\u0131z: Java programlama dili \u00e7ok g\u00fc\u00e7l\u00fcd\u00fcr. Java \u00f6\u011frenmek keyiflidir.<\/h2>\n<\/code><\/pre>\n<p>Ancak, bu son \u00f6rnekte orijinal stringin b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf yap\u0131s\u0131n\u0131 kaybedece\u011finizi unutmay\u0131n. E\u011fer orijinal yap\u0131y\u0131 korumak istiyorsan\u0131z, d\u00fczenli ifadeler (<code>re<\/code> mod\u00fcl\u00fc) daha uygun bir \u00e7\u00f6z\u00fcm olabilir.<\/p>\n<h3>Karakter Silme<\/h3>\n<p>Bir alt dizgeyi veya karakteri stringden tamamen kald\u0131rmak i\u00e7in <code>new<\/code> parametresini bo\u015f bir string (<code>\"\"<\/code>) olarak kullanabilirsiniz.<\/p>\n<h4>\u00d6rnek: Belirli Karakterleri Silme<\/h4>\n<pre><code class=\"language-python\">veri = \"Bug\u00fcn hava \u00e7ok g\u00fczel!!! Anla\u015ft\u0131k m\u0131?\"\ntemiz_veri = veri.replace(\"!\", \"\").replace(\"?\", \"\")\nprint(temiz_veri) # \u00c7\u0131kt\u0131: Bug\u00fcn hava \u00e7ok g\u00fczel Anla\u015ft\u0131k m\u0131\n<\/code><\/pre>\n<h3>Birden Fazla Farkl\u0131 De\u011fi\u015fiklik Yapma<\/h3>\n<p>E\u011fer bir string \u00fczerinde birden fazla farkl\u0131 alt dizgeyi de\u011fi\u015ftirmek istiyorsan\u0131z, <code>replace()<\/code> metodunu zincirleme (chaining) \u015feklinde kullanabilirsiniz.<\/p>\n<h4>\u00d6rnek: Zincirleme Kullan\u0131m<\/h4>\n<pre><code class=\"language-python\">url = \"https:\/\/www.example.com\/path\/to\/resource?id=123&name=test\"\ntemiz_url = url.replace(\"https:\/\/\", \"\").replace(\".com\", \"\").replace(\"\/\", \"_\")\nprint(temiz_url) # \u00c7\u0131kt\u0131: www.example_path_to_resource?id=123&name=test\n<\/code><\/pre>\n<p><strong>\u00d6nemli Not:<\/strong> Zincirleme yaparken i\u015flemlerin s\u0131ras\u0131 \u00f6nemlidir. \u00d6rne\u011fin, \u00f6nce &#8220;a&#8221;y\u0131 &#8220;b&#8221; ile, sonra &#8220;b&#8221;yi &#8220;c&#8221; ile de\u011fi\u015ftirirseniz, ba\u015flang\u0131\u00e7taki &#8220;a&#8221;lar en sonunda &#8220;c&#8221; olur.<\/p>\n<h3>\u00d6zel Karakterleri De\u011fi\u015ftirme<\/h3>\n<p>Yeni sat\u0131r (<code>\\n<\/code>), tab (<code>\\t<\/code>) gibi \u00f6zel karakterleri de <code>replace()<\/code> ile de\u011fi\u015ftirebilirsiniz.<\/p>\n<h4>\u00d6rnek: Yeni Sat\u0131r Karakterlerini Bo\u015flukla De\u011fi\u015ftirme<\/h4>\n<pre><code class=\"language-python\">\u00e7ok_sat\u0131rl\u0131_metin = \"Bu bir ilk sat\u0131r.\\nBu ikinci sat\u0131r.\\tBu da \u00fc\u00e7\u00fcnc\u00fc.\"\ntek_sat\u0131rl\u0131_metin = \u00e7ok_sat\u0131rl\u0131_metin.replace(\"\\n\", \" \").replace(\"\\t\", \" \")\nprint(tek_sat\u0131rl\u0131_metin) # \u00c7\u0131kt\u0131: Bu bir ilk sat\u0131r. Bu ikinci sat\u0131r. Bu da \u00fc\u00e7\u00fcnc\u00fc.\n<\/code><\/pre>\n<h2>replace() ve Di\u011fer Alternatifler<\/h2>\n<p><code>replace()<\/code> metodu \u00e7o\u011fu senaryo i\u00e7in yeterli olsa da, baz\u0131 durumlarda daha spesifik veya performansl\u0131 alternatifler mevcuttur.<\/p>\n<h3>str.translate() Metodu<\/h3>\n<p>E\u011fer \u00e7ok say\u0131da tek karakteri ba\u015fka tek karakterlerle de\u011fi\u015ftirmek istiyorsan\u0131z (yani bir karakter haritalamas\u0131 yap\u0131yorsan\u0131z), <code>str.translate()<\/code> metodu <code>replace()<\/code>&#8216;ten daha verimli olabilir. Bu metot, bir \u00e7eviri tablosu (translation table) kullanarak tek ge\u00e7i\u015fte bir\u00e7ok karakteri de\u011fi\u015ftirebilir.<\/p>\n<h4>\u00d6rnek: translate() ile Karakter Haritalamas\u0131<\/h4>\n<pre><code class=\"language-python\">metin = \"Hello World!\"\n<h2>'o'yu '0', 'l'yi '1' ile de\u011fi\u015ftir<\/h2>\n\u00e7eviri_tablosu = str.maketrans(\"ol\", \"01\")\nyeni_metin = metin.translate(\u00e7eviri_tablosu)\nprint(yeni_metin) # \u00c7\u0131kt\u0131: He110 W0r1d!\n\n<h2>Belirli karakterleri silmek i\u00e7in None kullanabiliriz<\/h2>\n\u00e7eviri_tablosu_sil = str.maketrans(\"\", \"\", \"aeiou\") # Sesli harfleri sil\nyeni_metin_sil = metin.translate(\u00e7eviri_tablosu_sil)\nprint(yeni_metin_sil) # \u00c7\u0131kt\u0131: Hll Wrld!\n<\/code><\/pre>\n<p><code>translate()<\/code>, \u00f6zellikle b\u00fcy\u00fck metinlerde ve \u00e7ok say\u0131da tek karakter de\u011fi\u015fimi gerekti\u011finde performans avantaj\u0131 sunar.<\/p>\n<h3>re.sub() Metodu (D\u00fczenli \u0130fadeler ile De\u011fi\u015ftirme)<\/h3>\n<p>E\u011fer de\u011fi\u015ftirmek istedi\u011finiz desen karma\u015f\u0131ksa, belirli bir kal\u0131ba uyuyorsa veya b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyars\u0131zl\u0131\u011f\u0131 gibi geli\u015fmi\u015f e\u015fle\u015ftirme \u00f6zelliklerine ihtiyac\u0131n\u0131z varsa, Python&#8217;\u0131n <code>re<\/code> (regular expression) mod\u00fcl\u00fcndeki <code>re.sub()<\/code> fonksiyonu daha uygun bir ara\u00e7t\u0131r.<\/p>\n<h4>\u00d6rnek: re.sub() ile D\u00fczenli \u0130fade Kullan\u0131m\u0131<\/h4>\n<pre><code class=\"language-python\">import re\n\nmetin = \"Bug\u00fcn 2023 y\u0131l\u0131nday\u0131z. Yar\u0131n 2024 olacak.\"\n\n<h2>T\u00fcm say\u0131lar\u0131 \"YIL\" ile de\u011fi\u015ftir<\/h2>\nyeni_metin_re = re.sub(r'\\d+', 'YIL', metin)\nprint(yeni_metin_re) # \u00c7\u0131kt\u0131: Bug\u00fcn YIL y\u0131l\u0131nday\u0131z. Yar\u0131n YIL olacak.\n\n<h2>B\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyars\u0131z de\u011fi\u015fim (re.IGNORECASE bayra\u011f\u0131 ile)<\/h2>\nmetin_case = \"Python \u00e7ok g\u00fczel. python \u00f6\u011freniyorum.\"\nyeni_metin_case_re = re.sub(r'python', 'JAVA', metin_case, flags=re.IGNORECASE)\nprint(yeni_metin_case_re) # \u00c7\u0131kt\u0131: JAVA \u00e7ok g\u00fczel. JAVA \u00f6\u011freniyorum.\n<\/code><\/pre>\n<p><code>re.sub()<\/code>, desen e\u015fle\u015ftirme konusunda \u00e7ok daha g\u00fc\u00e7l\u00fcd\u00fcr ve esneklik sa\u011flar, ancak \u00f6\u011frenme e\u011frisi <code>replace()<\/code>&#8216;e g\u00f6re daha diktir.<\/p>\n<h2>Sonu\u00e7<\/h2>\n<p>Python&#8217;daki <code>str.replace()<\/code> metodu, stringler \u00fczerinde alt dizge de\u011fi\u015ftirme i\u015flemleri i\u00e7in basit, anla\u015f\u0131l\u0131r ve \u00e7o\u011fu zaman yeterli bir ara\u00e7t\u0131r. Stringlerin de\u011fi\u015ftirilemez do\u011fas\u0131 gere\u011fi her zaman yeni bir string d\u00f6nd\u00fcrd\u00fc\u011f\u00fcn\u00fc unutmamak \u00f6nemlidir. Basit alt dizge de\u011fi\u015fimleri, karakter silme ve zincirleme operasyonlar\u0131 i\u00e7in ilk tercihiniz olmal\u0131d\u0131r.<\/p>\n<p>Ancak, tek karakter haritalamas\u0131 i\u00e7in <code>str.translate()<\/code> ve karma\u015f\u0131k desen e\u015fle\u015ftirme veya b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyars\u0131zl\u0131\u011f\u0131 gibi geli\u015fmi\u015f ihtiya\u00e7lar i\u00e7in <code>re.sub()<\/code> gibi daha g\u00fc\u00e7l\u00fc alternatiflerin varl\u0131\u011f\u0131n\u0131 bilmek, do\u011fru arac\u0131 do\u011fru zamanda se\u00e7menize yard\u0131mc\u0131 olacakt\u0131r.<\/p>\n<h3>S\u0131k\u00e7a Sorulan Sorular (SSS)<\/h3>\n<h4>1. <code>replace()<\/code> metodu b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyarl\u0131 m\u0131d\u0131r?<\/h4>\n<p>Evet, <code>replace()<\/code> metodu b\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyarl\u0131d\u0131r. &#8220;Python&#8221; ile &#8220;python&#8221; farkl\u0131 kabul edilir. B\u00fcy\u00fck\/k\u00fc\u00e7\u00fck harf duyars\u0131z de\u011fi\u015fim yapmak i\u00e7in stringi \u00f6nce <code>lower()<\/code> veya <code>upper()<\/code> ile tek bir duruma getirebilir veya <code>re.sub()<\/code> metodunu <code>re.IGNORECASE<\/code> bayra\u011f\u0131 ile kullanabilirsiniz.<\/p>\n<h4>2. <code>replace()<\/code> orijinal stringi de\u011fi\u015ftirir mi?<\/h4>\n<p>Hay\u0131r, Python&#8217;daki stringler de\u011fi\u015ftirilemez (immutable) oldu\u011fu i\u00e7in <code>replace()<\/code> metodu orijinal stringi de\u011fi\u015ftirmez. Bunun yerine, de\u011fi\u015fiklikleri i\u00e7eren <strong>yeni bir string<\/strong> d\u00f6nd\u00fcr\u00fcr. Bu yeni stringi kullanmak i\u00e7in bir de\u011fi\u015fkene ataman\u0131z gerekir.<\/p>\n<h4>3. Birden fazla farkl\u0131 alt dizgeyi tek bir i\u015flemde nas\u0131l de\u011fi\u015ftirebilirim?<\/h4>\n<p><code>replace()<\/code> metodunu zincirleme (chaining) \u015feklinde arka arkaya \u00e7a\u011f\u0131rarak birden fazla farkl\u0131 alt dizgeyi de\u011fi\u015ftirebilirsiniz: <code>metin.replace(\"eski1\", \"yeni1\").replace(\"eski2\", \"yeni2\")<\/code>. Alternatif olarak, e\u011fer de\u011fi\u015fimler \u00e7ok fazlaysa veya karma\u015f\u0131ksa, bir d\u00f6ng\u00fc i\u00e7inde veya <code>re.sub()<\/code> ile daha geli\u015fmi\u015f yakla\u015f\u0131mlar da kullanabilirsiniz.<\/p>\n<h4>4. <code>replace()<\/code> ile <code>re.sub()<\/code> aras\u0131ndaki temel fark nedir?<\/h4>\n<p><code>replace()<\/code> metodu sadece sabit alt dizgeleri (literal substrings) arar ve de\u011fi\u015ftirir. <code>re.sub()<\/code> ise d\u00fczenli ifadeler (regular expressions) kullanarak \u00e7ok daha karma\u015f\u0131k desenleri e\u015fle\u015ftirebilir ve de\u011fi\u015ftirebilir. E\u011fer ihtiyac\u0131n\u0131z basit bir alt dizge de\u011fi\u015fimi ise <code>replace()<\/code> tercih edilmeli; desen e\u015fle\u015ftirme karma\u015f\u0131ksa <code>re.sub()<\/code> kullan\u0131lmal\u0131d\u0131r.<\/p>\n<h4>5. Bir karakteri veya kelimeyi stringden silmek i\u00e7in <code>replace()<\/code> kullanabilir miyim?<\/h4>\n<p>Evet, silmek istedi\u011finiz karakteri veya kelimeyi <code>old<\/code> parametresine, <code>new<\/code> parametresine ise bo\u015f bir string (<code>\"\"<\/code>) vererek silebilirsiniz. \u00d6rne\u011fin: <code>metin.replace(\"silinecek_kelime\", \"\")<\/code>.<\/p>\n<p><\/body><\/p>\n","protected":false},"excerpt":{"rendered":"Python, metin i\u015fleme konusunda g\u00fc\u00e7l\u00fc ve esnek ara\u00e7lar sunar. Bu ara\u00e7lardan biri de string nesnelerinin ayr\u0131lmaz bir par\u00e7as\u0131 olan replace()","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"csco_page_header_type":"","csco_page_load_nextpost":"","csco_page_subscribe_form":"","csco_page_contact_form":"","footnotes":""},"categories":[1],"tags":[],"class_list":{"0":"post-39034","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-genel","7":"cs-entry","8":"cs-video-wrap"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v20.5 (Yoast SEO v25.3.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>replace() Metodunun Temel Kullan\u0131m\u0131 - Kodlar\u0131n Gizemli D\u00fcnyas\u0131<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/fatihsoysal.com\/blog\/replace-metodunun-temel-kullanimi\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"replace() Metodunun Temel Kullan\u0131m\u0131\" \/>\n<meta property=\"og:description\" content=\"Python, metin i\u015fleme konusunda g\u00fc\u00e7l\u00fc ve esnek ara\u00e7lar sunar. 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