{"id":38701,"date":"2026-02-05T20:41:23","date_gmt":"2026-02-05T17:41:23","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/?p=38701"},"modified":"2026-02-05T20:41:23","modified_gmt":"2026-02-05T17:41:23","slug":"giris-merge-sort-nedir","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/giris-merge-sort-nedir\/","title":{"rendered":"Giri\u015f: Merge Sort Nedir?"},"content":{"rendered":"<p><body><\/p>\n<h2>Giri\u015f: Merge Sort Nedir?<\/h2>\n<p>S\u0131ralama algoritmalar\u0131, bilgisayar bilimlerinin ve yaz\u0131l\u0131m geli\u015ftirmenin temel ta\u015flar\u0131ndan biridir. Verileri belirli bir d\u00fczene sokmak, arama i\u015flemlerini h\u0131zland\u0131rmak, raporlama ve analiz yeteneklerini art\u0131rmak i\u00e7in kritik \u00f6neme sahiptirler. Bir\u00e7ok s\u0131ralama algoritmas\u0131 aras\u0131nda Merge Sort (Birle\u015ftirmeli S\u0131ralama), &#8220;b\u00f6l ve y\u00f6net&#8221; (divide and conquer) paradigmalar\u0131n\u0131 en zarif \u015fekilde uygulayan, performans\u0131 garanti eden ve kararl\u0131 \u00f6zelliklere sahip g\u00fc\u00e7l\u00fc bir algoritmad\u0131r.<\/p>\n<p>Merge Sort, 1945 y\u0131l\u0131nda John von Neumann taraf\u0131ndan icat edilmi\u015ftir. Temel prensibi, s\u0131ralanacak diziyi s\u00fcrekli olarak daha k\u00fc\u00e7\u00fck alt dizilere b\u00f6lmek, bu alt dizileri ba\u011f\u0131ms\u0131z olarak s\u0131ralamak ve ard\u0131ndan s\u0131ral\u0131 alt dizileri birle\u015ftirerek nihai s\u0131ral\u0131 diziyi elde etmektir. Bu yakla\u015f\u0131m, \u00f6zellikle b\u00fcy\u00fck veri setleri \u00fczerinde tutarl\u0131 ve \u00f6ng\u00f6r\u00fclebilir bir performans sergilemesiyle bilinir.<\/p>\n<h2>Merge Sort&#8217;un \u00c7al\u0131\u015fma Prensibi ve Ad\u0131mlar\u0131<\/h2>\n<p>Merge Sort algoritmas\u0131, iki ana a\u015famadan olu\u015fur: B\u00f6lme (Divide) ve Birle\u015ftirme (Merge\/Conquer). Bu a\u015famalar \u00f6zyinelemeli (recursive) bir yap\u0131 i\u00e7inde \u00e7al\u0131\u015f\u0131r.<\/p>\n<h3>1. B\u00f6lme (Divide) A\u015famas\u0131<\/h3>\n<p>Bu a\u015famada, s\u0131ralanacak ana dizi, orta noktas\u0131ndan ikiye b\u00f6l\u00fcn\u00fcr. Bu b\u00f6lme i\u015flemi, her bir alt dizide yaln\u0131zca bir eleman kalana kadar \u00f6zyinelemeli olarak devam eder. Tek bir elemandan olu\u015fan bir dizi, tan\u0131m gere\u011fi zaten s\u0131ral\u0131d\u0131r. Bu a\u015famada herhangi bir s\u0131ralama i\u015flemi yap\u0131lmaz, sadece dizi par\u00e7alan\u0131r.<\/p>\n<p>\u00d6rnek bir dizi \u00fczerinden d\u00fc\u015f\u00fcnelim: <code>[38, 27, 43, 3, 9, 82, 10]<\/code><\/p>\n<ul>\n<li>Dizi ikiye b\u00f6l\u00fcn\u00fcr: <code>[38, 27, 43, 3]<\/code> ve <code>[9, 82, 10]<\/code><\/li>\n<li>Sol alt dizi tekrar b\u00f6l\u00fcn\u00fcr: <code>[38, 27]<\/code> ve <code>[43, 3]<\/code><\/li>\n<li>Sa\u011f alt dizi tekrar b\u00f6l\u00fcn\u00fcr: <code>[9, 82]<\/code> ve <code>[10]<\/code><\/li>\n<li>Bu i\u015flem, her alt dizide tek bir eleman kalana kadar devam eder: <code>[38], [27], [43], [3], [9], [82], [10]<\/code><\/li>\n<\/ul>\n<h3>2. Birle\u015ftirme (Merge\/Conquer) A\u015famas\u0131<\/h3>\n<p>B\u00f6lme a\u015famas\u0131n\u0131n sonunda elde edilen tek elemanl\u0131 (ve dolay\u0131s\u0131yla s\u0131ral\u0131) alt diziler, birle\u015ftirilmeye ba\u015flan\u0131r. Bu a\u015fama, Merge Sort&#8217;un as\u0131l s\u0131ralama mant\u0131\u011f\u0131n\u0131n uyguland\u0131\u011f\u0131 yerdir.<\/p>\n<p>\u0130ki s\u0131ral\u0131 alt dizi (\u00f6rne\u011fin <code>[27, 38]<\/code> ve <code>[3, 43]<\/code>) birle\u015ftirilirken, her iki dizinin ba\u015f\u0131ndan elemanlar kar\u015f\u0131la\u015ft\u0131r\u0131l\u0131r. Daha k\u00fc\u00e7\u00fck olan eleman yeni, birle\u015fik diziye yerle\u015ftirilir ve ilgili dizinin i\u015faret\u00e7isi bir sonraki elemana ilerletilir. Bu i\u015flem, her iki alt dizideki t\u00fcm elemanlar yeni diziye yerle\u015ftirilene kadar devam eder. E\u011fer bir dizide eleman kalmazsa, di\u011fer dizide kalan t\u00fcm elemanlar do\u011frudan yeni diziye eklenir.<\/p>\n<p>\u00d6rnek \u00fczerinden birle\u015ftirme ad\u0131mlar\u0131:<\/p>\n<ul>\n<li><code>[38]<\/code> ve <code>[27]<\/code> birle\u015fir -> <code>[27, 38]<\/code><\/li>\n<li><code>[43]<\/code> ve <code>[3]<\/code> birle\u015fir -> <code>[3, 43]<\/code><\/li>\n<li><code>[9]<\/code> ve <code>[82]<\/code> birle\u015fir -> <code>[9, 82]<\/code><\/li>\n<li><code>[10]<\/code> tek kal\u0131r.<\/li>\n<\/ul>\n<p>Daha sonra bu s\u0131ral\u0131 alt diziler tekrar birle\u015ftirilir:<\/p>\n<ul>\n<li><code>[27, 38]<\/code> ve <code>[3, 43]<\/code> birle\u015fir -> <code>[3, 27, 38, 43]<\/code><\/li>\n<li><code>[9, 82]<\/code> ve <code>[10]<\/code> birle\u015fir -> <code>[9, 10, 82]<\/code><\/li>\n<\/ul>\n<p>Son olarak, en b\u00fcy\u00fck iki s\u0131ral\u0131 alt dizi birle\u015ftirilir:<\/p>\n<ul>\n<li><code>[3, 27, 38, 43]<\/code> ve <code>[9, 10, 82]<\/code> birle\u015fir -> <code>[3, 9, 10, 27, 38, 43, 82]<\/code><\/li>\n<\/ul>\n<p>Bu s\u00fcre\u00e7, t\u00fcm dizi tek bir s\u0131ral\u0131 dizi haline gelene kadar devam eder.<\/p>\n<h2>Merge Sort Algoritmas\u0131n\u0131n Kod \u00d6rnekleri<\/h2>\n<h3>Java \u0130mplementasyonu<\/h3>\n<p>Java&#8217;da Merge Sort implementasyonu genellikle iki ana metottan olu\u015fur: ana \u00f6zyinelemeli <code>mergeSort<\/code> metodu ve iki s\u0131ral\u0131 alt diziyi birle\u015ftiren <code>merge<\/code> metodu.<\/p>\n<pre><code class=\"language-java\">\npublic class MergeSort {\n\n    \/\/ Ana Merge Sort metodu\n    public void mergeSort(int[] arr, int left, int right) {\n        if (left < right) {\n            \/\/ Diziyi ikiye b\u00f6l\n            int mid = (left + right) \/ 2;\n\n            \/\/ Sol ve sa\u011f yar\u0131y\u0131 \u00f6zyinelemeli olarak s\u0131rala\n            mergeSort(arr, left, mid);\n            mergeSort(arr, mid + 1, right);\n\n            \/\/ S\u0131ralanm\u0131\u015f yar\u0131lar\u0131 birle\u015ftir\n            merge(arr, left, mid, right);\n        }\n    }\n\n    \/\/ \u0130ki s\u0131ral\u0131 alt diziyi birle\u015ftiren yard\u0131mc\u0131 metod\n    void merge(int[] arr, int left, int mid, int right) {\n        \/\/ Ge\u00e7ici diziler i\u00e7in boyutlar\u0131 hesapla\n        int n1 = mid - left + 1;\n        int n2 = right - mid;\n\n        \/\/ Ge\u00e7ici diziler olu\u015ftur\n        int[] L = new int[n1];\n        int[] R = new int[n2];\n\n        \/\/ Verileri ge\u00e7ici dizilere kopyala\n        for (int i = 0; i < n1; i++)\n            L[i] = arr[left + i];\n        for (int j = 0; j < n2; j++)\n            R[j] = arr[mid + 1 + j];\n\n        \/\/ Ge\u00e7ici dizileri ana diziye birle\u015ftir\n        int i = 0, j = 0; \/\/ L ve R dizileri i\u00e7in ba\u015flang\u0131\u00e7 indeksleri\n        int k = left;     \/\/ Birle\u015ftirilen ana dizi i\u00e7in ba\u015flang\u0131\u00e7 indeksi\n\n        while (i < n1 &#038;&#038; j < n2) {\n            if (L[i] <= R[j]) {\n                arr[k] = L[i];\n                i++;\n            } else {\n                arr[k] = R[j];\n                j++;\n            }\n            k++;\n        }\n\n        \/\/ L'de kalan elemanlar\u0131 kopyala\n        while (i < n1) {\n            arr[k] = L[i];\n            i++;\n            k++;\n        }\n\n        \/\/ R'de kalan elemanlar\u0131 kopyala\n        while (j < n2) {\n            arr[k] = R[j];\n            j++;\n            k++;\n        }\n    }\n\n    \/\/ Test etmek i\u00e7in main metodu\n    public static void main(String[] args) {\n        int[] arr = {38, 27, 43, 3, 9, 82, 10};\n        System.out.println(\"S\u0131ralanmam\u0131\u015f dizi:\");\n        for (int x : arr) {\n            System.out.print(x + \" \");\n        }\n        System.out.println();\n\n        MergeSort ob = new MergeSort();\n        ob.mergeSort(arr, 0, arr.length - 1);\n\n        System.out.println(\"S\u0131ralanm\u0131\u015f dizi:\");\n        for (int x : arr) {\n            System.out.print(x + \" \");\n        }\n        System.out.println();\n    }\n}\n<\/code><\/pre>\n<h3>C \u0130mplementasyonu<\/h3>\n<p>C dilinde Merge Sort, bellek y\u00f6netimi ve pointer'lar nedeniyle biraz daha dikkat gerektirir, ancak temel mant\u0131k Java implementasyonu ile ayn\u0131d\u0131r.<\/p>\n<pre><code class=\"language-c\">\n#include <stdio.h>\n#include <stdlib.h> \/\/ malloc i\u00e7in\n\n\/\/ \u0130ki s\u0131ral\u0131 alt diziyi birle\u015ftiren yard\u0131mc\u0131 fonksiyon\nvoid merge(int arr[], int left, int mid, int right) {\n    int i, j, k;\n    int n1 = mid - left + 1;\n    int n2 = right - mid;\n\n    \/\/ Ge\u00e7ici diziler olu\u015ftur\n    int <em>L = (int <\/em>)malloc(n1 * sizeof(int));\n    int <em>R = (int <\/em>)malloc(n2 * sizeof(int));\n\n    \/\/ Verileri ge\u00e7ici dizilere kopyala\n    for (i = 0; i < n1; i++)\n        L[i] = arr[left + i];\n    for (j = 0; j < n2; j++)\n        R[j] = arr[mid + 1 + j];\n\n    \/\/ Ge\u00e7ici dizileri ana diziye birle\u015ftir\n    i = 0; \/\/ L dizisi i\u00e7in ba\u015flang\u0131\u00e7 indeksi\n    j = 0; \/\/ R dizisi i\u00e7in ba\u015flang\u0131\u00e7 indeksi\n    k = left; \/\/ Birle\u015ftirilen ana dizi i\u00e7in ba\u015flang\u0131\u00e7 indeksi\n\n    while (i < n1 &#038;&#038; j < n2) {\n        if (L[i] <= R[j]) {\n            arr[k] = L[i];\n            i++;\n        } else {\n            arr[k] = R[j];\n            j++;\n        }\n        k++;\n    }\n\n    \/\/ L'de kalan elemanlar\u0131 kopyala\n    while (i < n1) {\n        arr[k] = L[i];\n        i++;\n        k++;\n    }\n\n    \/\/ R'de kalan elemanlar\u0131 kopyala\n    while (j < n2) {\n        arr[k] = R[j];\n        j++;\n        k++;\n    }\n\n    \/\/ Ge\u00e7ici dizileri serbest b\u0131rak\n    free(L);\n    free(R);\n}\n\n\/\/ Ana Merge Sort fonksiyonu\nvoid mergeSort(int arr[], int left, int right) {\n    if (left < right) {\n        \/\/ Diziyi ikiye b\u00f6l\n        int mid = left + (right - left) \/ 2; \/\/ Ta\u015fmay\u0131 \u00f6nlemek i\u00e7in bu \u015fekilde hesaplan\u0131r\n\n        \/\/ Sol ve sa\u011f yar\u0131y\u0131 \u00f6zyinelemeli olarak s\u0131rala\n        mergeSort(arr, left, mid);\n        mergeSort(arr, mid + 1, right);\n\n        \/\/ S\u0131ralanm\u0131\u015f yar\u0131lar\u0131 birle\u015ftir\n        merge(arr, left, mid, right);\n    }\n}\n\n\/\/ Diziyi yazd\u0131rma fonksiyonu\nvoid printArray(int arr[], int size) {\n    int i;\n    for (i = 0; i < size; i++)\n        printf(\"%d \", arr[i]);\n    printf(\"\\n\");\n}\n\n\/\/ Test etmek i\u00e7in main fonksiyonu\nint main() {\n    int arr[] = {38, 27, 43, 3, 9, 82, 10};\n    int arr_size = sizeof(arr) \/ sizeof(arr[0]);\n\n    printf(\"S\u0131ralanmam\u0131\u015f dizi:\\n\");\n    printArray(arr, arr_size);\n\n    mergeSort(arr, 0, arr_size - 1);\n\n    printf(\"S\u0131ralanm\u0131\u015f dizi:\\n\");\n    printArray(arr, arr_size);\n\n    return 0;\n}\n<\/code><\/pre>\n<h3>Python \u0130mplementasyonu<\/h3>\n<p>Python'da list slicing (dizi dilimleme) \u00f6zelli\u011fi sayesinde Merge Sort implementasyonu daha k\u0131sa ve okunabilir olabilir. Genellikle <code>merge<\/code> i\u015flevi, ana <code>merge_sort<\/code> fonksiyonunun i\u00e7inde halledilir.<\/p>\n<pre><code class=\"language-python\">\ndef merge_sort(arr):\n    # Temel durum: Dizi 1 veya 0 elemanl\u0131 ise zaten s\u0131ral\u0131d\u0131r\n    if len(arr) <= 1:\n        return arr\n\n    # Diziyi ikiye b\u00f6l\n    mid = len(arr) \/\/ 2\n    left_half = arr[:mid]\n    right_half = arr[mid:]\n\n    # Sol ve sa\u011f yar\u0131y\u0131 \u00f6zyinelemeli olarak s\u0131rala\n    left_half = merge_sort(left_half)\n    right_half = merge_sort(right_half)\n\n    # S\u0131ralanm\u0131\u015f yar\u0131lar\u0131 birle\u015ftir\n    return merge(left_half, right_half)\n\ndef merge(left, right):\n    merged_arr = []\n    i = 0  # Sol dizi i\u00e7in indeks\n    j = 0  # Sa\u011f dizi i\u00e7in indeks\n\n    # \u0130ki diziyi kar\u015f\u0131la\u015ft\u0131rarak birle\u015ftir\n    while i < len(left) and j < len(right):\n        if left[i] <= right[j]:\n            merged_arr.append(left[i])\n            i += 1\n        else:\n            merged_arr.append(right[j])\n            j += 1\n\n    # Kalan elemanlar\u0131 ekle (varsa)\n    while i < len(left):\n        merged_arr.append(left[i])\n        i += 1\n\n    while j < len(right):\n        merged_arr.append(right[j])\n        j += 1\n    \n    return merged_arr\n\n<h2>Test etmek i\u00e7in \u00f6rnek<\/h2>\nif __name__ == \"__main__\":\n    arr = [38, 27, 43, 3, 9, 82, 10]\n    print(\"S\u0131ralanmam\u0131\u015f dizi:\", arr)\n    \n    sorted_arr = merge_sort(arr)\n    print(\"S\u0131ralanm\u0131\u015f dizi:\", sorted_arr)\n<\/code><\/pre>\n<h2>Merge Sort'un Performans\u0131 ve Pratik Kullan\u0131m Alanlar\u0131<\/h2>\n<h3>Zaman Karma\u015f\u0131kl\u0131\u011f\u0131 (Time Complexity)<\/h3>\n<p>Merge Sort'un en \u00f6nemli \u00f6zelliklerinden biri, zaman karma\u015f\u0131kl\u0131\u011f\u0131n\u0131n her durumda (en iyi, ortalama ve en k\u00f6t\u00fc durum) O(n log n) olmas\u0131d\u0131r. Bu, di\u011fer bir\u00e7ok s\u0131ralama algoritmas\u0131ndan (\u00f6rne\u011fin Quick Sort'un en k\u00f6t\u00fc durumu O(n^2) olabilir) daha tutarl\u0131 ve garantili bir performans\u0131 ifade eder.<\/p>\n<ul>\n<li><strong>O(log n) b\u00f6lme:<\/strong> Diziyi s\u00fcrekli ikiye b\u00f6lme i\u015flemi log n ad\u0131m s\u00fcrer.<\/li>\n<li><strong>O(n) birle\u015ftirme:<\/strong> Her b\u00f6lme seviyesinde, t\u00fcm elemanlar\u0131 birle\u015ftirmek i\u00e7in O(n) i\u015flem gerekir.<\/li>\n<\/ul>\n<p>Bu iki fakt\u00f6r birle\u015fti\u011finde, toplam zaman karma\u015f\u0131kl\u0131\u011f\u0131 O(n log n) olur. Bu, \u00f6zellikle b\u00fcy\u00fck veri setleri i\u00e7in olduk\u00e7a verimli bir performanst\u0131r.<\/p>\n<h3>Uzay Karma\u015f\u0131kl\u0131\u011f\u0131 (Space Complexity)<\/h3>\n<p>Merge Sort'un temel dezavantajlar\u0131ndan biri, birle\u015ftirme i\u015flemi s\u0131ras\u0131nda ge\u00e7ici diziler olu\u015fturmas\u0131 nedeniyle ek bellek alan\u0131 gerektirmesidir. Bu ek bellek ihtiyac\u0131 O(n) kadard\u0131r. Yani, s\u0131ralanacak eleman say\u0131s\u0131 artt\u0131k\u00e7a, kullan\u0131lan ek bellek alan\u0131 da do\u011frusal olarak artar. Belle\u011fin k\u0131s\u0131tl\u0131 oldu\u011fu sistemlerde bu bir sorun te\u015fkil edebilir.<\/p>\n<h3>Avantajlar\u0131 ve Dezavantajlar\u0131<\/h3>\n<h4>Avantajlar\u0131:<\/h4>\n<ul>\n<li><strong>Kararl\u0131l\u0131k (Stability):<\/strong> Ayn\u0131 de\u011fere sahip elemanlar\u0131n orijinal dizideki g\u00f6receli s\u0131ralar\u0131n\u0131 korur. Bu \u00f6zellik, baz\u0131 \u00f6zel s\u0131ralama senaryolar\u0131nda kritik \u00f6neme sahiptir.<\/li>\n<li><strong>Garanti Edilmi\u015f Performans:<\/strong> En k\u00f6t\u00fc durumda bile O(n log n) zaman karma\u015f\u0131kl\u0131\u011f\u0131na sahiptir.<\/li>\n<li><strong>Ba\u011fl\u0131 Listeler \u0130\u00e7in Uygunluk:<\/strong> Rastgele eri\u015fime ihtiya\u00e7 duymad\u0131\u011f\u0131 i\u00e7in (sadece ard\u0131\u015f\u0131k eri\u015fim), ba\u011fl\u0131 listeler \u00fczerinde Quick Sort'tan daha verimli \u00e7al\u0131\u015f\u0131r.<\/li>\n<li><strong>Harici S\u0131ralama (External Sorting):<\/strong> Belle\u011fe s\u0131\u011fmayan b\u00fcy\u00fck veri setlerini s\u0131ralamak i\u00e7in idealdir, \u00e7\u00fcnk\u00fc veriyi diskten okuyup yazabilir.<\/li>\n<\/ul>\n<h4>Dezavantajlar\u0131:<\/h4>\n<ul>\n<li><strong>Ek Bellek \u0130htiyac\u0131:<\/strong> O(n) ek alan gerektirir, bu da b\u00fcy\u00fck veri setlerinde \u00f6nemli bir dezavantaj olabilir.<\/li>\n<li><strong>Rek\u00fcrsif \u00c7a\u011fr\u0131 Y\u0131\u011f\u0131n\u0131 (Stack Overhead):<\/strong> Derin rek\u00fcrsif \u00e7a\u011fr\u0131lar, \u00f6zellikle \u00e7ok b\u00fcy\u00fck diziler i\u00e7in y\u0131\u011f\u0131n ta\u015fmas\u0131 (stack overflow) riskine yol a\u00e7abilir.<\/li>\n<li><strong>K\u00fc\u00e7\u00fck Diziler \u0130\u00e7in Yava\u015fl\u0131k:<\/strong> K\u00fc\u00e7\u00fck diziler i\u00e7in, daha basit algoritmalar (\u00f6rne\u011fin Insertion Sort) Merge Sort'un rek\u00fcrsif \u00e7a\u011fr\u0131 ve bellek kopyalama overhead'i nedeniyle daha h\u0131zl\u0131 olabilir.<\/li>\n<\/ul>\n<h3>Pratik Kullan\u0131m Alanlar\u0131<\/h3>\n<ul>\n<li><strong>B\u00fcy\u00fck Veri Setlerinin S\u0131ralanmas\u0131:<\/strong> Performans garantisi ve \u00f6l\u00e7eklenebilirli\u011fi sayesinde b\u00fcy\u00fck veri k\u00fcmeleri i\u00e7in tercih edilir.<\/li>\n<li><strong>Harici S\u0131ralama (External Sorting):<\/strong> Veri belle\u011fe s\u0131\u011fmad\u0131\u011f\u0131nda ve disk \u00fczerinde i\u015flem yap\u0131lmas\u0131 gerekti\u011finde (veri taban\u0131 y\u00f6netim sistemleri gibi).<\/li>\n<li><strong>Paralel S\u0131ralama Algoritmalar\u0131:<\/strong> B\u00f6l ve y\u00f6net yap\u0131s\u0131, paralel i\u015flemcilerde kolayca paralelle\u015ftirilebilir.<\/li>\n<li><strong>\u0130nversiyon Sayma (Inversion Counting):<\/strong> Bir dizideki tersine \u00e7evrilmi\u015f \u00e7iftleri saymak gibi baz\u0131 \u00f6zel problemlerin \u00e7\u00f6z\u00fcm\u00fcnde Merge Sort algoritmas\u0131 temel al\u0131n\u0131r.<\/li>\n<\/ul>\n<h2>Sonu\u00e7 ve S\u0131k\u00e7a Sorulan Sorular (SSS)<\/h2>\n<p>Merge Sort, \"b\u00f6l ve y\u00f6net\" stratejisini ustaca kullanan, kararl\u0131, verimli ve g\u00fcvenilir bir s\u0131ralama algoritmas\u0131d\u0131r. O(n log n) zaman karma\u015f\u0131kl\u0131\u011f\u0131 ile b\u00fcy\u00fck veri setleri i\u00e7in ideal bir se\u00e7imdir, ancak O(n) ek bellek ihtiyac\u0131, kaynak k\u0131s\u0131tl\u0131 ortamlarda dikkate al\u0131nmas\u0131 gereken bir fakt\u00f6rd\u00fcr. Java, C ve Python gibi farkl\u0131 dillerde kolayca implemente edilebilir ve modern yaz\u0131l\u0131m geli\u015ftirmede hala \u00f6nemli bir yere sahiptir.<\/p>\n<h3>S\u0131k\u00e7a Sorulan Sorular (SSS)<\/h3>\n<h4>Merge Sort ne zaman Quick Sort'tan daha iyidir?<\/h4>\n<p>Merge Sort, bellek alan\u0131 bir sorun te\u015fkil etmedi\u011finde, s\u0131ralama kararl\u0131l\u0131\u011f\u0131 (ayn\u0131 de\u011ferli elemanlar\u0131n g\u00f6receli s\u0131ras\u0131n\u0131 koruma) kritik oldu\u011funda ve en k\u00f6t\u00fc durum performans\u0131ndan (Quick Sort'un O(n^2) olabilen en k\u00f6t\u00fc durumu) ka\u00e7\u0131nmak istendi\u011finde Quick Sort'tan daha iyi bir se\u00e7enektir. Ayr\u0131ca, ba\u011fl\u0131 listeler gibi rastgele eri\u015fimin maliyetli oldu\u011fu veri yap\u0131lar\u0131nda Merge Sort daha avantajl\u0131d\u0131r.<\/p>\n<h4>Merge Sort neden kararl\u0131 bir algoritmad\u0131r?<\/h4>\n<p>Merge Sort, birle\u015ftirme a\u015famas\u0131nda ayn\u0131 de\u011fere sahip elemanlar kar\u015f\u0131la\u015ft\u0131r\u0131ld\u0131\u011f\u0131nda, sol alt diziden gelen eleman\u0131 \u00f6nce yerle\u015ftirerek kararl\u0131l\u0131k \u00f6zelli\u011fini korur. Bu, orijinal dizideki g\u00f6receli s\u0131ralar\u0131n\u0131n bozulmamas\u0131n\u0131 sa\u011flar.<\/p>\n<h4>Yerinde (in-place) Merge Sort m\u00fcmk\u00fcn m\u00fcd\u00fcr?<\/h4>\n<p>Teorik olarak O(1) ek alan kullanan yerinde Merge Sort implementasyonlar\u0131 mevcuttur, ancak bu implementasyonlar genellikle olduk\u00e7a karma\u015f\u0131kt\u0131r ve zaman karma\u015f\u0131kl\u0131\u011f\u0131n\u0131 art\u0131rabilir veya pratik kullan\u0131mda daha fazla kar\u015f\u0131la\u015ft\u0131rma gerektirebilir. Bu nedenle, \u00e7o\u011fu pratik implementasyonda O(n) ek bellek kullan\u0131m\u0131 kabul edilir.<\/p>\n<h4>Merge Sort'un iteratif versiyonu var m\u0131d\u0131r?<\/h4>\n<p>Evet, Merge Sort'un rek\u00fcrsif olmayan (iteratif) versiyonlar\u0131 da mevcuttur. Bu versiyonlar genellikle rek\u00fcrsif \u00e7a\u011fr\u0131 y\u0131\u011f\u0131n\u0131 ta\u015fmas\u0131 riskini \u00f6nlemek i\u00e7in kullan\u0131l\u0131r ve \u00f6zellikle \u00e7ok b\u00fcy\u00fck dizilerde tercih edilebilir. Ancak, iteratif implementasyonlar rek\u00fcrsif olanlara g\u00f6re genellikle biraz daha karma\u015f\u0131k bir yap\u0131ya sahiptir.<\/p>\n<p><\/body><\/p>\n","protected":false},"excerpt":{"rendered":"Giri\u015f: Merge Sort Nedir?\nS\u0131ralama algoritmalar\u0131, bilgisayar bilimlerinin ve yaz\u0131l\u0131m geli\u015ftirmenin temel ta\u015flar\u0131ndan biridir. Verileri belirl","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"csco_page_header_type":"","csco_page_load_nextpost":"","csco_page_subscribe_form":"","csco_page_contact_form":"","footnotes":""},"categories":[1],"tags":[],"class_list":{"0":"post-38701","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-genel","7":"cs-entry","8":"cs-video-wrap"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v20.5 (Yoast SEO v25.3.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Giri\u015f: Merge Sort Nedir? - Kodlar\u0131n Gizemli D\u00fcnyas\u0131<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/fatihsoysal.com\/blog\/giris-merge-sort-nedir\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Giri\u015f: Merge Sort Nedir?\" \/>\n<meta property=\"og:description\" content=\"Giri\u015f: Merge Sort Nedir? 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