{"id":24248,"date":"2025-06-16T22:00:14","date_gmt":"2025-06-16T19:00:14","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/leetcode-problem-2016-maximum-difference-between-increasing-elements\/"},"modified":"2025-06-16T22:00:14","modified_gmt":"2025-06-16T19:00:14","slug":"leetcode-problem-2016-maximum-difference-between-increasing-elements","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/leetcode-problem-2016-maximum-difference-between-increasing-elements\/","title":{"rendered":"LeetCode Problem 2016: Maximum Difference Between Increasing Elements"},"content":{"rendered":"<p>LeetCode Problem 2016: Maximum Difference Between Increasing Elements<\/p>\n<p>LeetCode&#8217;un 2016 numaral\u0131 problemine, yani &#8220;Maximum Difference Between Increasing Elements&#8221; problemine ho\u015f geldiniz! Bu makalede, problemi detayl\u0131 bir \u015fekilde ele alacak, \u00e7\u00f6z\u00fcm stratejilerini a\u00e7\u0131klayacak ve kod \u00f6rnekleri sunaca\u011f\u0131z.  \u00d6ncelikle problem tan\u0131m\u0131n\u0131 daha iyi anlamak i\u00e7in, sorunun ne oldu\u011funu inceleyelim.<\/p>\n<h2>Problem Tan\u0131m\u0131<\/h2>\n<p>Problem, size bir dizi tam say\u0131 (<code>nums<\/code>) veriliyor ve bu dizide artan s\u0131rada yer alan iki eleman\u0131n aras\u0131ndaki maksimum fark\u0131 bulman\u0131z\u0131 istiyor.  Ba\u015fka bir deyi\u015fle,  <code>nums[i] < nums[j]<\/code> ve <code>i < j<\/code> ko\u015fullar\u0131n\u0131 sa\u011flayan t\u00fcm <code>i<\/code> ve <code>j<\/code> \u00e7iftleri i\u00e7in <code>nums[j] - nums[i]<\/code> fark\u0131n\u0131n maksimum de\u011ferini bulmal\u0131s\u0131n\u0131z.  E\u011fer b\u00f6yle bir \u00e7ift yoksa, 0 d\u00f6nd\u00fcrmelisiniz.<\/p>\n<h2>\u00c7\u00f6z\u00fcm Stratejileri<\/h2>\n<p>Bu problemi \u00e7\u00f6zmek i\u00e7in birka\u00e7 farkl\u0131 strateji izleyebilirsiniz.  En yayg\u0131n ve verimli y\u00f6ntemlerden biri, tek bir ge\u00e7i\u015f (single pass) kullanmakt\u0131r.  Bu y\u00f6ntemde, diziyi soldan sa\u011fa do\u011fru tarayarak, \u015fimdiye kadar g\u00f6rd\u00fc\u011f\u00fcm\u00fcz en k\u00fc\u00e7\u00fck say\u0131y\u0131 (<code>min_val<\/code>) ve maksimum fark\u0131 (<code>max_diff<\/code>) takip ederiz.<\/p>\n<p>Her bir say\u0131 i\u00e7in, \u015fu ad\u0131mlar\u0131 izleriz:<\/p>\n<ol>\n<li>E\u011fer mevcut say\u0131, <code>min_val<\/code>'den k\u00fc\u00e7\u00fckse, <code>min_val<\/code>'i g\u00fcncelleriz. \u00c7\u00fcnk\u00fc daha k\u00fc\u00e7\u00fck bir ba\u015flang\u0131\u00e7 noktas\u0131, daha b\u00fcy\u00fck bir fark elde etme olas\u0131l\u0131\u011f\u0131n\u0131 art\u0131r\u0131r.<\/li>\n<li>E\u011fer mevcut say\u0131, <code>min_val<\/code>'den b\u00fcy\u00fckse,  mevcut say\u0131 ile <code>min_val<\/code> aras\u0131ndaki fark\u0131 hesaplar ve <code>max_diff<\/code> ile kar\u015f\u0131la\u015ft\u0131r\u0131r\u0131z. Daha b\u00fcy\u00fckse, <code>max_diff<\/code>'i g\u00fcncelleriz.<\/li>\n<\/ol>\n<p>Bu i\u015flemlerden sonra, <code>max_diff<\/code> de\u011feri, aranan maksimum fark\u0131 verecektir.<\/p>\n<h2>Kod \u00d6rne\u011fi (Python)<\/h2>\n<pre><code>\ndef max_difference(nums):\n    \"\"\"\n    Bir dizideki artan elemanlar aras\u0131ndaki maksimum fark\u0131 bulur.\n\n    Args:\n        nums: Tam say\u0131lardan olu\u015fan bir dizi.\n\n    Returns:\n        Artan elemanlar aras\u0131ndaki maksimum fark.  E\u011fer b\u00f6yle bir \u00e7ift yoksa 0 d\u00f6nd\u00fcr\u00fcr.\n    \"\"\"\n    min_val = float('inf')  # sonsuzluk ile ba\u015flat\u0131yoruz\n    max_diff = 0\n\n    for num in nums:\n        if num < min_val:\n            min_val = num\n        elif num > min_val:\n            max_diff = max(max_diff, num - min_val)\n\n    return max_diff\n\n<\/code><\/pre>\n<h2>Karma\u015f\u0131kl\u0131k Analizi<\/h2>\n<p>Bu \u00e7\u00f6z\u00fcm\u00fcn zaman karma\u015f\u0131kl\u0131\u011f\u0131 O(n)'dir, \u00e7\u00fcnk\u00fc diziyi yaln\u0131zca bir kez tar\u0131yoruz.  Uzay karma\u015f\u0131kl\u0131\u011f\u0131 ise O(1)'dir, \u00e7\u00fcnk\u00fc sabit miktarda ek bellek kullan\u0131yoruz.<\/p>\n<h2>Sonu\u00e7<\/h2>\n<p>LeetCode'un 2016 numaral\u0131 problemi, basit ama etkili bir \u00e7\u00f6z\u00fcm gerektiren g\u00fczel bir problemdir.  Tek bir ge\u00e7i\u015f kullanarak,  zaman ve bellek a\u00e7\u0131s\u0131ndan verimli bir \u015fekilde \u00e7\u00f6z\u00fcm \u00fcretebiliriz.  Umar\u0131m bu makale, problemi anlaman\u0131za ve \u00e7\u00f6zmenize yard\u0131mc\u0131 olmu\u015ftur.  Daha fazla LeetCode \u00e7\u00f6z\u00fcm\u00fc ve programlama ile ilgili i\u00e7erikler i\u00e7in <a href=\"https:\/\/fatihsoysal.com\">fatihsoysal.com<\/a> adresini ziyaret edebilirsiniz.<\/p>\n<p>#Etiketler: LeetCode, Problem 2016, Maximum Difference, Increasing Elements, Python, Algoritma, Veri Yap\u0131lar\u0131, Programlama, \u00c7\u00f6z\u00fcm, Kod \u00d6rne\u011fi, Zaman Karma\u015f\u0131kl\u0131\u011f\u0131, Uzay Karma\u015f\u0131kl\u0131\u011f\u0131<\/p>\n","protected":false},"excerpt":{"rendered":"LeetCode Problem 2016: Maximum Difference Between Increasing Elements LeetCode&#8217;un 2016 numaral\u0131 problemine, yani &#8220;Maximum Difference Between Increasing Elements&#8221;&hellip;","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"csco_page_header_type":"","csco_page_load_nextpost":"","csco_page_subscribe_form":"","csco_page_contact_form":"","footnotes":""},"categories":[1],"tags":[],"class_list":{"0":"post-24248","1":"post","2":"type-post","3":"status-publish","4":"format-standard","6":"category-genel","7":"cs-entry","8":"cs-video-wrap"},"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v20.5 (Yoast SEO v25.3.1) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>LeetCode Problem 2016: Maximum Difference Between Increasing Elements<\/title>\n<meta name=\"description\" content=\"LeetCode&#039;un 2016 numaral\u0131 problemine, yani &quot;Maximum Difference Between Increasing Elements&quot; problemine ho\u015f geldiniz! 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