{"id":14650,"date":"2025-03-09T08:00:17","date_gmt":"2025-03-09T05:00:17","guid":{"rendered":"https:\/\/fatihsoysal.com\/blog\/frontend-roportaj-sorusu-paralel-gorev-limiti\/"},"modified":"2025-03-09T08:00:17","modified_gmt":"2025-03-09T05:00:17","slug":"frontend-roportaj-sorusu-paralel-gorev-limiti","status":"publish","type":"post","link":"https:\/\/fatihsoysal.com\/blog\/frontend-roportaj-sorusu-paralel-gorev-limiti\/","title":{"rendered":"Frontend R\u00f6portaj Sorusu: Paralel G\u00f6rev Limiti"},"content":{"rendered":"

<\/p>\n

Frontend R\u00f6portaj Sorusu: Paralel G\u00f6rev Limiti<\/p>\n

Frontend geli\u015ftirici pozisyonlar\u0131nda s\u0131k\u00e7a kar\u015f\u0131la\u015f\u0131lan bir r\u00f6portaj sorusu, “paralel g\u00f6rev limiti” konusudur. Bu soru, aday\u0131n asenkron programlama becerilerini, performans optimizasyonuna olan yakla\u015f\u0131m\u0131n\u0131 ve problem \u00e7\u00f6zme yetene\u011fini de\u011ferlendirmeyi ama\u00e7lar. \u00d6rne\u011fin, ayn\u0131 anda \u00e7ok say\u0131da resim y\u00fcklenmesi gerekti\u011finde, s\u0131n\u0131rs\u0131z paralel i\u015flem, taray\u0131c\u0131n\u0131n kaynaklar\u0131n\u0131 t\u00fcketebilir ve performans sorunlar\u0131na yol a\u00e7abilir. Bu sorunun cevab\u0131, taray\u0131c\u0131n\u0131n kaynaklar\u0131n\u0131 etkili bir \u015fekilde kullanarak, ayn\u0131 anda i\u015flenen g\u00f6rev say\u0131s\u0131n\u0131 s\u0131n\u0131rlayan bir \u00e7\u00f6z\u00fcm \u00fcretmeyi gerektirir.<\/p>\n

\u00d6ncelikle, problemi daha iyi anlamak i\u00e7in bir senaryo d\u00fc\u015f\u00fcnelim: Bir e-ticaret sitesi d\u00fc\u015f\u00fcn\u00fcn. Bu sitede y\u00fczlerce \u00fcr\u00fcn\u00fcn resmi var ve bunlar\u0131n hepsi ayn\u0131 anda y\u00fcklenmeye \u00e7al\u0131\u015f\u0131l\u0131yor. Bu durum, taray\u0131c\u0131n\u0131n donmas\u0131na veya yava\u015flamas\u0131na sebep olabilir. \u0130\u015fte burada “paralel g\u00f6rev limiti” devreye giriyor. Amac\u0131m\u0131z, ayn\u0131 anda en fazla belirli say\u0131da (\u00f6rne\u011fin 5) resmin y\u00fcklenmesini sa\u011flamak ve kalan resimlerin ise \u00f6nceki resimler y\u00fcklendikten sonra s\u0131raya girmesini garantilemektir. Bu, taray\u0131c\u0131n\u0131n kaynaklar\u0131n\u0131 daha verimli kullanmam\u0131z\u0131 ve kullan\u0131c\u0131 deneyimini iyile\u015ftirmemizi sa\u011flar.<\/p>\n

\u00c7\u00f6z\u00fcm: Async\/Await ve Promise.all<\/h2>\n

Bu sorunun yayg\u0131n \u00e7\u00f6z\u00fcmlerinden biri, async\/await<\/code> ve Promise.all<\/code> fonksiyonlar\u0131n\u0131 birlikte kullanmakt\u0131r. async\/await<\/code>, asenkron i\u015flemleri senkron kod gibi yazmam\u0131z\u0131 sa\u011flar ve okunabilirli\u011fi art\u0131r\u0131r. Promise.all<\/code> ise, birden fazla Promise’\u0131n sonu\u00e7lar\u0131n\u0131 bekler ve hepsi \u00e7\u00f6z\u00fcmlendi\u011finde tek bir Promise d\u00f6nd\u00fcr\u00fcr. Bunlar\u0131 birle\u015ftirerek, paralel g\u00f6rev say\u0131s\u0131n\u0131 kontrol edebiliriz. A\u015fa\u011f\u0131da bu tekni\u011fi g\u00f6steren bir \u00f6rnek kod bulunmaktad\u0131r:<\/p>\n

\nasync function parallelTaskLimit(tasks, maxParallel) {\n  const results = [];\n  let running = 0;\n  const queue = [...tasks];\n\n  function processNext() {\n    if (queue.length === 0 && running === 0) return;\n    while (running < maxParallel && queue.length > 0) {\n      running++;\n      const task = queue.shift();\n      task().then(result => {\n        results.push(result);\n        running--;\n        processNext();\n      });\n    }\n  }\n\n  processNext();\n  return await Promise.all(results);\n}\n\n\/\/\u00d6rnek kullan\u0131m:\nconst tasks = Array.from({ length: 10 }, (_, i) => () => new Promise(resolve => setTimeout(() => resolve(Task ${i + 1}), 1000)));\nparallelTaskLimit(tasks, 3).then(results => console.log(results));\n\n<\/code><\/pre>\n
Bu kodda,  maxParallel<\/code> parametresi ayn\u0131 anda \u00e7al\u0131\u015facak g\u00f6rev say\u0131s\u0131n\u0131 belirler.  Queue mant\u0131\u011f\u0131yla s\u0131radaki g\u00f6revler i\u015flenir.  Her bir g\u00f6revin tamamlanmas\u0131,  processNext()<\/code> fonksiyonu sayesinde bir sonraki g\u00f6revin ba\u015flat\u0131lmas\u0131n\u0131 tetikler. Bu sayede, ayn\u0131 anda en fazla maxParallel<\/code> kadar g\u00f6rev \u00e7al\u0131\u015f\u0131r ve taray\u0131c\u0131 kaynaklar\u0131 daha verimli kullan\u0131l\u0131r.<\/p>\n
Alternatif Yakla\u015f\u0131mlar ve \u0130pu\u00e7lar\u0131<\/h2>\n
Ba\u015fka alternatifler de mevcuttur.  \u00d6rne\u011fin, bir g\u00f6rev kuyru\u011fu sistemi kullanarak,  g\u00f6revleri daha sofistike bir \u015fekilde y\u00f6netebilirsiniz. Bu, daha b\u00fcy\u00fck \u00f6l\u00e7ekli uygulamalar i\u00e7in daha uygun olabilir. Ancak,  bu basit \u00f6rnek,  r\u00f6portaj sorusunu cevaplamak i\u00e7in yeterli bir temel olu\u015fturur.  Bu t\u00fcr sorularda sadece teknik bilgi de\u011fil, ayn\u0131 zamanda problem \u00e7\u00f6zme becerisi ve performans odakl\u0131 bir d\u00fc\u015f\u00fcnce tarz\u0131 da olduk\u00e7a \u00f6nemlidir.<\/p>\n
Sonu\u00e7 olarak,  “paralel g\u00f6rev limiti” sorusu,  frontend geli\u015ftiriciler i\u00e7in \u00f6nemli bir konuyu ele almaktad\u0131r.  Bu soruyu cevaplayabilmek i\u00e7in, asenkron programlama kavramlar\u0131na hakim olmak ve performans optimizasyonuna duyarl\u0131 olmak gerekmektedir.  Bu makalede ele ald\u0131\u011f\u0131m\u0131z y\u00f6ntemler,  sizlere bu konuda yol g\u00f6sterici olacakt\u0131r. Daha fazla bilgi i\u00e7in fatihsoysal.com<\/a> adresini ziyaret edebilirsiniz.<\/p>\n
Ek olarak, konuyu daha detayl\u0131 anlamak i\u00e7in a\u015fa\u011f\u0131daki kayna\u011f\u0131 inceleyebilirsiniz: https:\/\/dev.to\/moniv9\/frontend-interview-question-parallel-task-limit-118o<\/a><\/p>\n
#Etiketler<\/h3>\n
Frontend, Javascript, Async Await, Promise, Parallel Task Limit, R\u00f6portaj Sorusu, Web Geli\u015ftirme, Performans Optimizasyonu, Promise.all<\/p>\n
<\/body>
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Bu soru, aday\u0131n asenkron programlama becerilerini, performans optimizasyonuna olan yakla\u015f\u0131m\u0131n\u0131 ve problem \u00e7\u00f6zme yetene\u011fini de\u011ferlendirmeyi ama\u00e7lar. \u00d6rne\u011fin, ayn\u0131 anda \u00e7ok say\u0131da resim y\u00fcklenmesi gerekti\u011finde, s\u0131n\u0131rs\u0131z paralel i\u015flem, taray\u0131c\u0131n\u0131n kaynaklar\u0131n\u0131 t\u00fcketebilir ve performans sorunlar\u0131na yol a\u00e7abilir. 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